Solve the equation: $-(x-5)=x-2$
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Solve the equation: $-(x-5)=x-2$
-(x-5) = x-2 becomes -x + 5 = x - 2. Adding x to both sides gives 5 = 2x - 2. Adding 2 gives 7 = 2x, so x = 7/2.
First, distribute the negative sign on the left side to get -x + 5 = x - 2. Adding x to both sides yields 5 = 2x - 2. Then, add 2 to both sides to get 7 = 2x. Dividing by 2 gives x = 7/2.