Solve the equation $\displaystyle\frac { x-5 }{ 7 } =\displaystyle\frac { x+3 }{ 2 } $
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Solve the equation $\displaystyle\frac { x-5 }{ 7 } =\displaystyle\frac { x+3 }{ 2 } $
Cross-multiply: 2(x - 5) = 7(x + 3). 2x - 10 = 7x + 21. -31 = 5x, so x = -31/5.
Cross-multiply the fractions to get 2(x - 5) = 7(x + 3). Distributing the numbers gives 2x - 10 = 7x + 21. Subtracting 2x and then 21 from both sides yields -31 = 5x. Dividing by 5 gives x = -31/5.