Multiple choice

A solid cylinder of density $800\ kg\ m^{-3}$ floats in water. The percentage volume of solid cylinder outside the water is

  1. $10$
  2. $80$
  3. $50$
  4. $20$
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D Correct answer
Explanation

By Archimedes' principle, the fraction of volume submerged is equal to the ratio of the object's density to the fluid's density. Density of water is 1000 kg/m^3. Submerged volume = 800/1000 = 80%. Volume outside = 100% - 80% = 20%.

AI explanation

Using Archimedes' principle, a floating object displaces a volume of water equal to its own weight. Since the density of the cylinder is 800 kg/m^3 and water is 1000 kg/m^3, the fraction of the cylinder's volume that must be submerged to displace an equal mass of water is 800 divided by 1000, which is 0.8. This means 80 percent of the cylinder is submerged, leaving 20 percent of its volume outside the water.

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