Multiple choice

A $15$ liter of a mixture contains $20$% alcohol and rest water. if $3 $ liter of water is added in it, find the % of alcohol in the new mixture.

  1. $16.66$ %
  2. $12.26$ %
  3. $18.88$ %
  4. $21.27$%
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A Correct answer
Explanation

Initial alcohol = 20% of 15 = 3 liters. Total volume becomes 15 + 3 = 18 liters. New percentage = (3 / 18) * 100 = 100 / 6 = 16.66%.

AI explanation

The initial 15 liter mixture contains 20 percent alcohol, which is 3 liters. Adding 3 liters of water increases the total volume to 18 liters, while the alcohol remains at 3 liters. Using the percentage formula, the new concentration is (3 divided by 18) multiplied by 100, resulting in 16.66 percent.

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