Multiple choice

A flower bucket in the shape of a frustum cone with the top and bottom circles of radii $5$ in. and $10$ in. It's depth is $15$ in. Find its volume.

  1. $375\pi \space\ in^3$
  2. $475\pi \space\ in^3$
  3. $875\pi \space\ in^3$
  4. $675\pi \space\ in^3$
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

The volume of a frustum is (1/3)pi*h(R^2 + r^2 + R*r). Here R=10, r=5, h=15. Volume = (1/3)pi*15(100 + 25 + 50) = 5*pi*(175) = 875*pi.

AI explanation

Using the frustum of a cone volume formula, V = (1/3)pi*h(R^2 + r^2 + R*r), substitute the bottom radius R as 10 inches, the top radius r as 5 inches, and the depth h as 15 inches. The sum of the squared radii and their product is 10^2 + 5^2 + 10*5, which equals 100 + 25 + 50, resulting in 175. Multiplying this by the height 15 and dividing by 3 gives 875, so the volume is 875*pi cubic inches.

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