Multiple choice

Solve the system of equation; $\left | x^{2}-2x \right |+y=1$; $x^{2}+\left | y \right |=1$. Tick the option which is not the solution of the equations.

  1. $(x=0, y=1) $
  2. $(x=1, y=0)$
  3. $\displaystyle \left ( x=y=\frac{1-\sqrt{5}}{2} \right )$.
  4. $(x=1, y=1)$
Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

Substituting x=1, y=1 into the first equation: |1^2 - 2(1)| + 1 = |-1| + 1 = 2, which does not equal 1. Thus, (1, 1) is not a solution.

AI explanation

To check which pair is not a solution, substitute the values from option D into the given equations. For x = 1 and y = 1, the first equation gives |1 - 2| + 1 = 2, which does not equal 1. Therefore, x = 1, y = 1 is not a solution of the system.

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