Cylinder A has a radius 2 cm and a height of 4 cm. Cylinder B has a radius 1 cm and a height of 5 cm. Which cylinder has the greater surface area? (use $\displaystyle \pi =3.14$).

The total surface area of a cylinder is calculated as $2\pi r^2 + 2\pi rh$. For cylinder A with radius $2$ cm and height $4$ cm, the surface area is $2 \times 3.14 \times 2^2 + 2 \times 3.14 \times 2 \times 4 = 25.12 + 50.24 = 75.36$ cm$^2$. For cylinder B with radius $1$ cm and height $5$ cm, the surface area is $2 \times 3.14 \times 1^2 + 2 \times 3.14 \times 1 \times 5 = 6.28 + 31.4 = 37.68$ cm$^2$. Cylinder A has a greater surface area.

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