Multiple choice

A cylindrical tower is $5$ metres in diameter and $14$ metres high. The cost of white washing its curved surface at $50$ paise per $\text{m}^{2}$ is _____.

  1. Rs. $90$
  2. Rs. $97$
  3. Rs. $110$
  4. Rs. $95$
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Curved surface area = 2 * pi * r * h = 2 * (22/7) * 2.5 * 14 = 220 m^2. Cost = 220 * 0.50 = 110.

AI explanation

Using the curved surface area formula for a cylinder, CSA = πdh, we substitute the diameter of 5 m and height of 14 m to get (22/7) * 5 * 14 = 220 m^2. The cost of white washing is calculated at 50 paise, or Rs. 0.5, per m^2. Multiplying 220 by 0.5 gives a total cost of Rs. 110.

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