Multiple choice

Equal weights ${C}{2}{H}{6}$ and hydrogen are mixed in an empty container at ${0}^{o}C$. The fraction of total pressure exerted by hydrogen is-

  1. $1:2$
  2. $1:1$
  3. $1:16$
  4. $15:16$
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D Correct answer
Explanation

Equal weights means moles of H2 = w/2 and moles of C2H6 = w/30. Mole fraction of H2 = (w/2) / (w/2 + w/30) = (1/2) / (16/30) = (1/2) * (30/16) = 15/16.

AI explanation

Assuming an equal weight of 16 grams for both C2H6 and H2, the moles of C2H6 are 16 divided by 30, and the moles of H2 are 16 divided by 2. The mole fraction of hydrogen is calculated by dividing its moles, which is 8, by the total moles of 8.533, resulting in a fraction of 15 divided by 16. Therefore, the fraction of the total pressure exerted by hydrogen is 15:16.

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