A cylinder container with radius $56$ m contains sufficient water to submerge a rectangular solid of iron with dimensions $12 m \times 14 m \times 10 m$. Find the rise in the level of water when solid is completely submerged.

Using the volume displacement method, the rise in water level equals the volume of the submerged object divided by the base area of the cylinder. The volume of the rectangular solid is (12)(14)(10) = 1680 cubic meters. The base area of the cylinder is (22/7)(56)(56) = 9856 square meters. Dividing the solid's volume by the cylinder's base area gives 1680 / 9856 = 0.17045 meters. The rise in the water level is approximately 0.170 m.

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