Multiple choice

The roots of the following quadratic equation Real and equal. $3x^2$ - 2$\sqrt{6}x$ + 2 = 0

  1. True

  2. False
Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

For 3x^2 - 2sqrt(6)x + 2 = 0, the discriminant is (-2sqrt(6))^2 - 4(3)(2) = 24 - 24 = 0. A zero discriminant means the roots are real and equal.

AI explanation

Using the discriminant method for 3x^2 - 2(sqrt(6))x + 2 = 0, we find D = b^2 - 4ac. Substituting the values gives D = (-2(sqrt(6)))^2 - 4(3)(2) = 24 - 24 = 0. A discriminant equal to zero confirms that the roots are real and equal.

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