Multiple choice

The roots of the following quadratic equation are Real and equal. $3x^2-4\sqrt3x+4=0$

  1. True

  2. False
Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

For 3x^2 - 4*sqrt(3)x + 4 = 0, the discriminant D = (-4*sqrt(3))^2 - 4(3)(4) = 48 - 48 = 0. Since D=0, the roots are real and equal.

AI explanation

For 3x^2 - 4(sqrt(3))x + 4 = 0, the discriminant D = b^2 - 4ac determines the nature of the roots. Substituting the values gives D = (-4(sqrt(3)))^2 - 4(3)(4) = 48 - 48 = 0. Because the discriminant is exactly zero, the roots of the quadratic equation are real and equal.

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