Multiple choice

A solid piece of iron of dimensions $66 cm \times 49 cm \times 12 cm$ is moulded into a sphere. The radius of the sphere i s

  1. $7 cm$
  2. $3 cm$
  3. $21 cm$
  4. $14 cm$
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C Correct answer
Explanation

The iron's volume is 66 x 49 x 12 = 38808 cubic centimeters. Equating this to the volume of a sphere gives r = 21 cm.

AI explanation

The volume of the iron piece is 66 * 49 * 12 = 38808 cubic cm, which equals the volume of the sphere. Using the sphere volume formula (4/3)pi*r^3, we get (4/3)(22/7)*r^3 = 38808. Solving for r^3 gives 9261, so the radius r is the cube root of 9261, which is 21 cm.

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