Multiple choice

Find the lateral or curved surface area of a closed cylindrical petrol storage tank is $4.2m$ in diameter and $4.5m$ high.

  1. $2\times \cfrac{22}{7}\times \cfrac{21}{10}\times \cfrac{45}{10}{m}^{2}$
  2. $2\times \cfrac{12}{7}\times \cfrac{21}{10}\times \cfrac{45}{10}{m}^{2}$
  3. $2\times \cfrac{22}{7}\times \cfrac{11}{10}\times \cfrac{45}{10}{m}^{2}$
  4. $2\times \cfrac{22}{7}\times \cfrac{21}{10}\times \cfrac{35}{10}{m}^{2}$
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A Correct answer
Explanation

Curved surface area = 2 * pi * r * h. Diameter = 4.2, so radius r = 2.1 = 21/10. Height h = 4.5 = 45/10. Area = 2 * (22/7) * (21/10) * (45/10). This matches option A.

AI explanation

The lateral or curved surface area of a cylinder is calculated using the formula 2 times pi times r times h. The given diameter of 4.2 m provides a radius of 2.1 m, which is equivalent to 21 divided by 10 m, and the height is 4.5 m, equivalent to 45 divided by 10 m. Substituting these values into the formula gives 2 times 22 divided by 7 times 21 divided by 10 times 45 divided by 10 m squared.

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