What are the nature of quadratic equation $x^2 + 3x + 4 = 0$ ?
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What are the nature of quadratic equation $x^2 + 3x + 4 = 0$ ?
Real and Distinct
Not Real
Real and Equal
None of these
The discriminant D = b^2 - 4ac. For x^2 + 3x + 4 = 0, D = 3^2 - 4(1)(4) = 9 - 16 = -7. Since D < 0, the roots are not real.
We determine the nature of the roots by finding the discriminant, which is b squared minus 4ac. For the equation x squared plus 3x plus 4 equals zero, we calculate 3 squared minus 4 times 1 times 4. This simplifies to 9 minus 16, yielding negative 7. A negative discriminant means the quadratic equation has no real roots, so the roots are not real.