Determine the nature of the roots of the equation: $x^2-8x+12=0$
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Determine the nature of the roots of the equation: $x^2-8x+12=0$
Real and unequal
Real and equal
Imaginary
None of these
For x^2 - 8x + 12 = 0, the discriminant D = b^2 - 4ac = (-8)^2 - 4(1)(12) = 64 - 48 = 16. Since D > 0 and is a perfect square, the roots are real, rational, and unequal.
The nature of the roots is determined by the discriminant, which is calculated as D = b^2 - 4ac. For the equation x^2 - 8x + 12 = 0, the discriminant is (-8)^2 - 4(1)(12) = 64 - 48 = 16. Since 16 is a positive number, the equation has real and unequal roots.