Solve the following quadratic equation using quadratic formula: $9x^2-9x+2=0$
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Solve the following quadratic equation using quadratic formula: $9x^2-9x+2=0$
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Using the quadratic formula x = (-b +/- sqrt(b^2 - 4ac)) / 2a: x = (9 +/- sqrt(81 - 72)) / 18 = (9 +/- 3) / 18. Roots are 12/18 = 2/3 and 6/18 = 1/3.
We solve 9x^2 - 9x + 2 = 0 using the quadratic formula, where x = (-b + sqrt(b^2 - 4ac)) / 2a. Here, a = 9, b = -9 and c = 2, making the discriminant (-9)^2 - 4(9)(2) equal to 9. The square root of the discriminant is 3, so the roots are calculated as (9 + 3) / 18 and (9 - 3) / 18. This yields the solution set {2/3, 1/3}.