Solve the following quadratic equation using quadratic formula: $x^2-7x+12=0$
- $\left \{ 4, 3 \right \}$
- $\left \{ 4, -3 \right \}$
- $\left \{ -4, -3 \right \}$
-
None of these
Reveal answer
Fill a bubble to check yourself
A
Correct answer
Explanation
For x^2 - 7x + 12 = 0, factor the quadratic: (x - 4)(x - 3) = 0. The roots are x = 4 and x = 3.
AI explanation
Using the quadratic formula, x equals the quantity negative b plus or minus the square root of b squared minus 4 a c divided by 2 a. For the equation x squared minus 7 x plus 12 equals 0, the values are a equals 1, b equals negative 7, and c equals 12. Substituting these gives x equals 7 plus or minus the square root of negative 7 squared minus 4 times 1 times 12, all divided by 2. The discriminant is 49 minus 48, which equals 1, so x equals 7 plus or minus 1 divided by 2. This yields x equals 4 or x equals 3, so the solution set is 4 and 3.