Find the monthly payment of a person who secures a loan of $ $4,000$ which he will pay back in $36$ months with a monthly interest rate of $0.01$ such that $M = \dfrac {rP}{1 - \left (\dfrac {1}{1 + r}\right )^{t}}$ where $M$ is the monthly payment, $r$ is the monthly decimal interest rate, $P$ is the amount borrowed and $t$ is the number of months it will take to repay the loan.

Substituting the given values into the loan payment formula, we get M = (0.01 * 4000) / (1 - (1 / (1 + 0.01))^36), which simplifies to 40 / (1 - (1 / 1.01)^36). This evaluates to 40 / (1 - 0.6989), yielding approximately 132.86.

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