Multiple choice

A 3L container at 3 atm pressure consist a mixture of $N_2$ gas and $H_2O$ vapours. Solid sphere of volume 0.5L is also present in same container. What will be the pressure of gas, if volume of container is reduced to 2L, at same temperature (AQ. tension = 0.2 atm)?

  1. 5.4 atm

  2. 4.2 atm

  3. 4.87 atm

  4. 5 atm
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Initial gas volume = 3L - 0.5L = 2.5L. Initial pressure of gas = 3 - 0.2 = 2.8 atm. New volume = 2L - 0.5L = 1.5L. Using P1V1 = P2V2: 2.8 * 2.5 = P2 * 1.5. P2 = 7 / 1.5 = 4.66. Total pressure = 4.66 + 0.2 = 4.86 atm.

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