The equation is (2x - 1)(3x/2 + 1) = 0. Setting each factor to zero gives 2x - 1 = 0 (x = 1/2) and 3x/2 + 1 = 0 (x = -2/3). The sum of the roots is 1/2 - 2/3 = 3/6 - 4/6 = -1/6.
Setting each linear factor of (2x - 1)(3x/2 + 1) = 0 to zero gives the roots x = 1/2 and x = -2/3. The sum of these roots is 1/2 + (-2/3). Finding a common denominator of 6 gives the sum as 3/6 - 4/6 = -1/6.