Multiple choice

Find the roots of the equation: $\displaystyle 2{ y }^{ 2 }-6y-20=0$

  1. $2, 5$
  2. $-2, 5$
  3. $-2, -5$

  4. None
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Dividing the equation by 2 gives y^2 - 3y - 10 = 0. Factoring this quadratic results in (y - 5)(y + 2) = 0, so the roots are 5 and -2.

AI explanation

First, simplify the equation 2y squared minus 6y minus 20 equals 0 by dividing by 2 to get y squared minus 3y minus 10 equals 0. We then factor by finding two numbers that multiply to negative 10 and add to negative 3, which are negative 5 and 2. This gives the factors y plus 2 and y minus 5, so setting y plus 2 equals 0 and y minus 5 equals 0 yields the roots negative 2 and 5.

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