If $\alpha, \beta$ are the roots of equation $x^2 + 2(a - 3)x + 9 = 0$, $a\in R$ and $\alpha < 6 < \beta$, then $a <-\displaystyle{\frac{3}{4}}$.
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If $\alpha, \beta$ are the roots of equation $x^2 + 2(a - 3)x + 9 = 0$, $a\in R$ and $\alpha < 6 < \beta$, then $a <-\displaystyle{\frac{3}{4}}$.