Multiple choice

When 100 ml of a $O_{2} - O_{3}$ mixture was passed through turpentine, there was the reduction of volume by 20 ml. If 100ml of such a mixture is heated, what will be the increase in volume?

  1. $10\ ml$
  2. $20\ ml$
  3. $30\ ml$
  4. $25\ ml$
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A Correct answer
Explanation

Turpentine absorbs O3. 20 ml reduction means 20 ml of the 100 ml is O3. Heating O3 causes it to convert to O2: 2O3 -> 3O2. The 20 ml of O3 will produce 30 ml of O2. The net increase in volume is 30 - 20 = 10 ml.

AI explanation

When the 100 ml mixture is passed through turpentine, only the ozone (O3) reacts, so the 20 ml volume reduction means the mixture contains 20 ml of O3 and 80 ml of O2. If this same mixture is heated, the ozone decomposes completely according to the chemical equation 2O3 -> 3O2. Solving using Gay-Lussac's law of gaseous volumes, the 20 ml of O3 decomposes to produce 30 ml of O2. This creates a net increase in the total gas volume of 30 ml - 20 ml = 10 ml.

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