A single coin is tossed $5$ times. What is the probability of getting at least one head?
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A single coin is tossed $5$ times. What is the probability of getting at least one head?
The probability of getting no heads in 5 tosses is (1/2)^5 = 1/32. The probability of getting at least one head is 1 - P(no heads) = 1 - 1/32 = 31/32.
The probability of getting at least one head is best found by calculating the complementary probability of getting no heads at all. When a coin is tossed 5 times, the probability of getting all tails is (1 divided by 2) raised to the power of 5, which is 1 divided by 32. Subtracting this from 1 gives the probability of at least one head. The calculation is 1 minus (1 divided by 32), which equals 31 divided by 32.