Multiple choice

The chord of contact of tangent from a point $P$ to a circle passes through $Q$. If ${ l }{ 1 }$ and ${ l }{ 2 }$ are the lengths of the tangents from $P$ and $Q$ to the circle, then $PQ$ is equal to $\sqrt { { { l }{ 1 } }^{ 2 }+{ { l }{ 2 } }^{ 2 } } $

  1. Assertion is true, Reason is true and reason is correct explanation for Statement-1.

  2. Assertion is true, Reason is true and Reason is NOT correct explanation for Assertion.

  3. Assertion is true, Reason is false

  4. Assertion is false, Reason is true

Reveal answer Fill a bubble to check yourself
A Correct answer
AI explanation

By the pole and polar relationship, if the polar of point P passes through point Q, then the polar of Q passes through P. This forms a right triangle with the center of the circle, where the lines joining the center to P and Q are perpendicular, making the angle at the center 90 degrees. Using the Pythagorean theorem on the distances from the center to P (which equals the length of the tangent l1) and the center to Q (which equals l2), the distance PQ is exactly the square root of (l1 squared plus l2 squared).