Multiple choice

What is the concentration of the solution produced when $8.0\ mL$ of water is added to $2.0\ mL$ of $0.4\ M$ $Ca{Cl}_{2}$?

  1. $0.08\ M$
  2. $0.2\ M$
  3. $0.1\ M$
  4. $0.04\ M$
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A Correct answer
Explanation

Using the dilution formula M1V1 = M2V2, where M1=0.4, V1=2.0, and V2 = 2.0 + 8.0 = 10.0. 0.4 * 2.0 = M2 * 10.0, so M2 = 0.8 / 10 = 0.08 M.

AI explanation

Using the dilution equation M1V1 equals M2V2, the final volume of the solution is 2.0 mL plus 8.0 mL, which is 10.0 mL. The final concentration is 0.4 M times 2.0 mL divided by 10.0 mL. This equals 0.8 divided by 10, giving a final concentration of 0.08 M.

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