Multiple choice

If you mix 3 litres of 0.5M $NaCl$ with 9 litres of 0.2777 M $NaCl$ what will the concentration of the final solution be, assuming that volumes are additive?

  1. 0.33 M

  2. 0.39 M

  3. 0.5777 M

  4. 0.6777 M

  5. None of the above
Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

Total moles = (3 * 0.5) + (9 * 0.2777) = 1.5 + 2.4993 = 3.9993. Total volume = 3 + 9 = 12. Concentration = 3.9993 / 12 = 0.333 M.

AI explanation

Using the mixture formula for final molarity, C equals (C1V1 plus C2V2) divided by (V1 plus V2). Plugging in the values gives (0.5 times 3 plus 0.2777 times 9) divided by (3 plus 9). This calculates to 3.9993 divided by 12, yielding a concentration of 0.33 M.

Keep practicing — related questions