Multiple choice

Find the sum of first 32 terms of the arithmetic series if $a_1 = 12$ and $a_{32} = 40$.

  1. $830$
  2. $831$
  3. $832$
  4. $834$
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C Correct answer
Explanation

Sum = (n/2) * (a_1 + a_n) = (32/2) * (12 + 40) = 16 * 52 = 832.

AI explanation

The sum of an arithmetic series is found using the formula S_n = n/2(a_1 + a_n). Substituting n = 32, the first term = 12, and the 32nd term = 40, we calculate the sum as 32/2(12 + 40). This simplifies to 16 * 52, which equals 832.

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