If $'r'$ and $'s'$ are the roots of the equation $ax^2+bc+c=0$, then the value of $\displaystyle\frac{1}{r^2}+\frac{1}{s^2}$ is equal to

Assuming the intended equation is ax^2+bx+c=0, the sum of the roots r+s is -b/a and the product rs is c/a. The expression 1/r^2 + 1/s^2 simplifies to (r+s)^2 - 2rs divided by (rs)^2. Substituting the sum and product values gives ((-b/a)^2 - 2c/a) / (c/a)^2, which evaluates to (b^2-2ac)/c^2.

• Thanks
• Wrong explanation