Multiple choice

A shopkeeper buys $x$ kg sugar for Rs. $y$ and sells it at Rs $z$ per kg. Find profit percent.

  1. $\displaystyle \frac{(zx - y)}{x} \times 100$%
  2. $\displaystyle \frac{(zx - y)}{y} \times 100$%
  3. $\displaystyle \frac{(z-x )}{y} \times 100$%
  4. $\displaystyle \frac{(z - xy)}{y} \times 100$%
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Cost price (CP) for x kg is y, so CP per kg is y/x. Selling price (SP) per kg is z. Profit per kg = z - (y/x) = (zx - y)/x. Profit percent = (Profit / CP) * 100 = [((zx - y)/x) / (y/x)] * 100 = ((zx - y)/y) * 100.

AI explanation

The total cost price for the sugar is y, and the total selling price for x kg at z per kg is zx. The profit is calculated as total selling price minus total cost price, giving zx - y. Using the profit percentage formula, (Profit / Cost Price) * 100, the expression is ((zx - y) / y) * 100%.