$p^{th}$ term of the series $\displaystyle \left ( 3-\frac{1}{n} \right )+\left ( 3-\frac{2}{n} \right )+\left ( 3-\frac{3}{n} \right ).......$ will be
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$p^{th}$ term of the series $\displaystyle \left ( 3-\frac{1}{n} \right )+\left ( 3-\frac{2}{n} \right )+\left ( 3-\frac{3}{n} \right ).......$ will be