Check if the series is an $AP.$ Find the common difference $d$. Also, find the next three terms. $-10, -6, -2 , 2.....$.
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Check if the series is an $AP.$ Find the common difference $d$. Also, find the next three terms. $-10, -6, -2 , 2.....$.
None of these
The series is -10, -6, -2, 2. The difference between consecutive terms is -6 - (-10) = 4, -2 - (-6) = 4, 2 - (-2) = 4. It is an AP with d=4. The next terms are 2+4=6, 6+4=10, 10+4=14.
The difference between consecutive terms is constant, as -6 minus -10 is 4, and -2 minus -6 is also 4. This means the sequence is an arithmetic progression with a common difference of 4. To find the next three terms, keep adding 4 to the previous term, giving 2 plus 4 equals 6, 6 plus 4 equals 10, and 10 plus 4 equals 14.