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Multiple choice

The sum of the series 1.2.3+2.3.4+...3.4.5.+...to n terms is

  1. $n(n+1)(n+2)$
  2. $(n+1)(n+2)(n+3)$
  3. $\frac { 1 }{ 4 } n(n+1)(n+2)(n+3)$
  4. $\frac { 1 }{ 4 } (n+1)(n+2)(n+3)$
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