Multiple choice Find the quadratic equation having one root : $2\sqrt3\,-\,4$ $x^2\,-\,4\sqrt{3}x\,-\,4\,=\,0$ $x^2\,-\,8x\,+\,4\,=\,0$ $x^2\,+\,4\sqrt{3}x\,-\,4\,=\,0$ $x^2\,-\,8x\,-\,4\,=\,0$ Reveal answer Fill a bubble to check yourself A Correct answer