Roots of quadratic equation $3y^2\,+\,7y\,+\,4\,=\,0$ are
- $\displaystyle\,y\,=\,-1,\,\frac{-4}{3}$
- $\displaystyle\,y\,=\,2,\,\frac{-4}{3}$
- $\displaystyle\,y\,=\,-2,\,\frac{-4}{3}$
- $\displaystyle\,y\,=\,-1,\,\frac{-4}{5}$
Reveal answer
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A
Correct answer
Explanation
Factoring 3y^2 + 7y + 4 = 0 gives (3y + 4)(y + 1) = 0. Setting each factor to zero yields y = -4/3 and y = -1.
AI explanation
Using the factorization method for 3y^2 + 7y + 4 = 0, split the middle term to get 3y^2 + 3y + 4y + 4 = 0. Factoring by grouping gives 3y(y + 1) + 4(y + 1) = 0, which simplifies to (3y + 4)(y + 1) = 0. Setting each factor to zero results in the roots y = -4/3 and y = -1.