Roots of the quadratic equation $4x^2\,+\,7x\,+\,2\,=\,0$, are
- $\displaystyle\,x\,=\,\frac{-7\,\pm\,\sqrt{11}}{8}$
- $\displaystyle\,x\,=\,\frac{-7\,\pm\,\sqrt{-17}}{8}$
- $\displaystyle\,x\,=\,\frac{-7\,\pm\,\sqrt{17}}{8}$
- $\displaystyle\,x\,=\,\frac{-4\,\pm\,\sqrt{17}}{8}$
Reveal answer
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C
Correct answer
Explanation
Using the quadratic formula x = (-7 +/- sqrt(49 - 4*4*2)) / 8 = (-7 +/- sqrt(49 - 32)) / 8 = (-7 +/- sqrt(17)) / 8.
AI explanation
For the quadratic equation 4x^2 + 7x + 2 = 0, the coefficients are a = 4, b = 7, and c = 2. Using the quadratic formula, x = (-b plus or minus the square root of (b^2 - 4ac)) divided by 2a. Substituting the values gives x = (-7 plus or minus the square root of (49 - 32)) divided by 8, which simplifies to x = (-7 plus or minus the square root of 17) divided by 8.