Multiple choice

Find the roots of following quadratic equation $x^2\,+\,3x\,-\,2\,=\,0$

  1. $\displaystyle\,x\,=\,\frac{-3\,\pm\,\sqrt{15}}{2}$
  2. $\displaystyle\,x\,=\,\frac{-3\,\pm\,\sqrt{17}}{2}$
  3. $\displaystyle\,x\,=\,\frac{-3\,\pm\,\sqrt{19}}{2}$
  4. $\displaystyle\,x\,=\,\frac{-3\,\pm\,\sqrt{21}}{2}$
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B Correct answer
Explanation

Using quadratic formula x = (-b +/- sqrt(b^2 - 4ac)) / 2a. Here a=1, b=3, c=-2. x = (-3 +/- sqrt(9 - 4*1*-2)) / 2 = (-3 +/- sqrt(17)) / 2.

AI explanation

Using the quadratic formula, the roots are x = (-3 plus or minus sqrt(9 + 8)) / 2. This simplifies to x = (-3 plus or minus sqrt(17)) / 2.

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