The $10^{th}$ term of the series 5,8,11,14,.........is
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The $10^{th}$ term of the series 5,8,11,14,.........is
32
35
38
185
This is an arithmetic progression with a = 5 and d = 3. The 10th term = a + (n-1)d = 5 + (9 * 3) = 5 + 27 = 32.
Using the formula for the nth term of an arithmetic progression, we have the first term as 5 and a common difference of 3. To find the 10th term, we use the formula a + (n - 1)d. Substituting the values gives 5 + (10 - 1)3 = 32.