Multiple choice

An unbiased die is tossed twice. What is the probability of getting a $4,5$ or $6$ on the first toss and a $1,2,3$ or $4$ on the second toss?

  1. $\cfrac{1}{3}$
  2. $\cfrac{2}{3}$
  3. $\cfrac{3}{4}$
  4. $\cfrac{5}{6}$
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A Correct answer
Explanation

Probability of getting 4, 5, or 6 on first toss is 3/6 = 1/2. Probability of getting 1, 2, 3, or 4 on second toss is 4/6 = 2/3. Since events are independent, total probability = (1/2) * (2/3) = 1/3.

AI explanation

The probability of getting a 4, 5, or 6 on the first toss is 3/6, which equals 1/2. The probability of getting a 1, 2, 3, or 4 on the second toss is 4/6, which equals 2/3. Since the tosses are independent, multiply the probabilities to get 1/2 times 2/3, which is 1/3. The result is 1/3.

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