Multiple choice

Find the roots of following quadratic equation $7x\,+\,1\,=\,6x^2$

  1. $\displaystyle\,x\,=\,\frac{5\,\pm\,\sqrt{73}}{12}$
  2. $\displaystyle\,x\,=\,\frac{2\,\pm\,\sqrt{73}}{12}$
  3. $\displaystyle\,x\,=\,\frac{3\,\pm\,\sqrt{73}}{12}$
  4. $\displaystyle\,x\,=\,\frac{7\,\pm\,\sqrt{73}}{12}$
Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

Rearrange to 6x^2 - 7x - 1 = 0. Using quadratic formula x = [-b +/- sqrt(b^2 - 4ac)] / 2a: x = [7 +/- sqrt(49 - 4(6)(-1))] / 12 = [7 +/- sqrt(49 + 24)] / 12 = [7 +/- sqrt(73)] / 12.

AI explanation

Rearranging gives 6x^2 - 7x - 1 = 0. Using the quadratic formula, the roots are x = (7 plus or minus sqrt(49 + 24)) / 12, which simplifies to x = (7 plus or minus sqrt(73)) / 12.

Keep practicing — related questions