A gaseous mixture contains ${ CH }{ 4 }$ and ${ CH }{ 2 }{ H }_{ 6 }$ in equimolecular proportion. The weight of $2.24$ liters of this mixture at NTP is:

Using the molar volume at NTP, 2.24 liters of gas corresponds to 0.1 moles. Since the gases are in an equimolecular proportion, the average molar mass of the mixture is the average of methane (16 g/mol) and ethane (30 g/mol), which equals 23 g/mol. Multiplying the average molar mass by the number of moles gives a total mass of 2.3 g.

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