Which term of the sequence $ 3, 8, 13, 18, ........$ is $498$.
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Which term of the sequence $ 3, 8, 13, 18, ........$ is $498$.
This is an arithmetic progression with a = 3 and d = 5. The n-th term is a + (n-1)d = 498. 3 + (n-1)5 = 498, so (n-1)5 = 495, n-1 = 99, n = 100.
The sequence is an arithmetic progression with first term 3 and common difference 5. The nth term formula is a + (n - 1)d. Setting the term to 498 gives 3 + (n - 1)*5 = 498, so 5(n - 1) = 495 and n - 1 = 99. This means n equals 100, making it the 100th term.