How many terms of the series 1+3+9+ ...sum to 364?
Reveal answer
Fill a bubble to check yourself
How many terms of the series 1+3+9+ ...sum to 364?
5
6
4
3
This is a geometric series with a=1, r=3. Sum = a(r^n - 1)/(r-1) = 1(3^n - 1)/2 = 364. 3^n - 1 = 728. 3^n = 729. Since 3^6 = 729, n = 6.
The series 1 + 3 + 9 + ... is a geometric progression with first term 1 and common ratio 3. The sum of n terms formula is a(r^n - 1)/(r - 1). Setting the sum to 364 gives (3^n - 1)/(3 - 1) = 364, so 3^n - 1 = 728 and 3^n = 729. Since 3^6 equals 729, there are 6 terms.