Find the probability of getting two heads when five coins are tossed.
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Find the probability of getting two heads when five coins are tossed.
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Binomial probability: P(X=k) = nCk * p^k * q^(n-k). n=5, k=2, p=0.5. P(X=2) = 5C2 * (0.5)^5 = 10 / 32 = 5/16.
Using the binomial distribution formula, the probability of getting exactly r heads in n tosses is nCr * (1/2)^n. For getting exactly two heads in five coin tosses, the calculation is 5C2 * (1/2)^5. This equals 10 * (1/32), which simplifies to 5/16.