If two dice are thrown simultaneously, then the probability of getting a doublet or a total of $6$ is
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If two dice are thrown simultaneously, then the probability of getting a doublet or a total of $6$ is
Total outcomes = 36. Doublets: (1,1), (2,2), (3,3), (4,4), (5,5), (6,6) [6 outcomes]. Total of 6: (1,5), (2,4), (3,3), (4,2), (5,1) [5 outcomes]. Overlap: (3,3) [1 outcome]. Total favorable = 6 + 5 - 1 = 10. Probability = 10/36 = 5/18.
When two dice are thrown, there are 36 possible outcomes. The number of doublets, where both dice show the same number, is 6, and the number of outcomes totaling exactly 6 is 5: (1, 5), (5, 1), (2, 4), (4, 2), and (3, 3). By the addition rule of probability, we add the doublets and the sums of 6, then subtract the one overlapping outcome of (3, 3), resulting in 6 plus 5 minus 1 equals 10 favorable outcomes. The probability is therefore 10 divided by 36, which simplifies to 5/18.