Multiple choice

$1$ g of ice at $0^{\circ}C$ is mixed $1$ g of stream at $100^{\circ}C$. After thermal equilibrium is achieved, the temperature of the mixture is

  1. $100^{\circ}C$
  2. $55^{\circ}C$
  3. $75^{\circ}C$
  4. $0^{\circ}C$
Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

1g of steam at 100C releases 540 calories to condense into water at 100C. 1g of ice at 0C requires 80 calories to melt into water at 0C. The remaining heat (540 - 80 = 460 calories) will raise the temperature of the 2g of water. Since 460 calories is more than enough to raise 2g of water to 100C (which takes 2 * 100 = 200 calories), the mixture will reach 100C.

AI explanation

Evaluate the heat exchange by calculating the heat needed to melt the ice completely and the heat released if the steam condenses completely. The 1 g of ice requires 80 calories to melt, plus 100 calories to heat to 100 degrees Celsius, requiring a total of 180 calories to reach 100 degrees. The 1 g of steam releases 540 calories just by condensing into water, which is far more heat than the ice requires; this excess heat remains in the system as the steam continues to boil off. The final temperature of the mixture is 100 degrees Celsius.

Keep practicing — related questions