Multiple choice

Choose the correct answer from the alternative given. PQ and RS are two parallel chords of a circle. If PQ = 30 cm, RS = 16 cm and distance between PQ and RS is 23 cm, then the radius of the circle.

  1. $12$
  2. $17$
  3. $34$
  4. $19$
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Let center be O. Distance from O to PQ is d1, to RS is d2. d1^2 + 15^2 = r^2. d2^2 + 8^2 = r^2. d1+d2 = 23. Solving d1^2 + 225 = d2^2 + 64 => d2^2 - d1^2 = 161 => (d2-d1)(23) = 161 => d2-d1 = 7. d2+d1 = 23, so 2*d2 = 30, d2=15, d1=8. r^2 = 15^2 + 8^2 = 225 + 64 = 289. r = 17.

AI explanation

Since the chords are on opposite sides of the center, the sum of their distances from the center equals 23 cm. Using the Pythagorean theorem on the right triangles formed by the radius, half the chord length, and the distance to the center, we set up the equations r squared equals x squared plus 8 squared and r squared equals (23 minus x) squared plus 15 squared. Equating the two expressions gives x squared plus 64 equals 529 minus 46x plus x squared plus 225, which simplifies to 46x equals 690, so x equals 15. Substituting x back into the first equation gives r squared equals 15 squared plus 8 squared, which equals 225 plus 64 equals 289, meaning the radius is 17 cm.