Selecting 10 balls from 3 identical colors where balls of each color are infinite is a stars and bars problem, giving a total of 12C2 = 66 total ways. The probability of getting at least one ball of each color is 1 minus the probability of missing at least one color. The number of ways to choose all 10 balls from only 2 colors is 3 x 11C2 = 165, and the number of ways to choose all 10 balls from a single color is 3, so the probability of the complement is (165 - 3)/666 = 5/11, making the target probability 1 - 5/11 = 6/11.