Multiple choice

If both the roots of the equation ${ x }^{ 2 }\quad -\quad 6ax\quad +\quad 2\quad -\quad 2a\quad +\quad { 9a }^{ 2 }\quad =\quad 0$ exceed 3, then

$a\quad >\quad \frac { 9 }{ 11 } $
$a\quad \ge \quad \frac { 9 }{ 11 } $
$a\quad >\quad \frac { 11 }{ 9 } $
$a\quad <\quad \frac { 11 }{ 9 } $

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